If $1.26 g$ of oxalic acid is dissolved in $250 m L$ of solution, find its normality. The equivalent mass of oxalic acid is $63$ .

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Solution

Molecule of oxalic acid $H_{2} C_{2} o_{4} .2 H_{2} O = 126 g / m o l$
$1.26 g$ is dissolved in $250 M L$
$\to 5.04 g$ is dissolved in $1000 M L$
Normality $= M a s s o f s o l u t e / d n^{3} s o l u t i o n E q u i v a l e n t w e i g h t$
$= \frac{5.04}{63}$
$= 0.08 N$

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If 1.26 g of oxalic acid is dissolved in 250 mL of solution, find its normality. The equivalent mass of oxalic acid is 63.

Molecule of oxalic acid H2C2o4.2H2O=126g/mol1.26g is dissolved in 250ML→5.04g is dissolved in 1000MLNormality =Massofsolute/dn3solutionEquivalentweight=5.0463=0.08N

If $1.26 g$ of oxalic acid is dissolved in $250 m L$ of solution, find its normality. The equivalent mass of oxalic acid is $63$ .

Molecule of oxalic acid $H_{2} C_{2} o_{4} .2 H_{2} O = 126 g / m o l$
$1.26 g$ is dissolved in $250 M L$
$\to 5.04 g$ is dissolved in $1000 M L$
Normality $= M a s s o f s o l u t e / d n^{3} s o l u t i o n E q u i v a l e n t w e i g h t$
$= \frac{5.04}{63}$
$= 0.08 N$