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Question

If (1+2x+3x2)10=a0+a1x+a2x2+.....+a20x20, then a1 equals

A
6
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B
8
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C
210
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D
None of these
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Solution

The correct option is C None of these
Given
(1+2x+3x2)10=a0+a1x+a2x2++a20x20
Differentiating Both the sides w.r.t 'x'
10(1+2x+3x2)9(2+6x)=a1+2a2x++a20.20x19
put x = 0
10×1×2=a1
a1=20


1074798_1183712_ans_00d6d6bfc25c43598c66044fa5b96683.png

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