wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If 13+23+...+93=2025, then (0.11)3+(0.22)3+...(0.99)3 will be _________.

A
0.2695
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2.695
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
3.695
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.3695
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2.695
Given: 13+23+...+93=2025
(0.11)3+(0.22)3+...+(0.99)3=(0.11×1)3+(0.11×2)3+......+(0.11×9)3=(0.11)3[13+23+...93]0.001331×2025=2.6952752.695

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Identities for Irrational Numbers
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon