If 13-23- p 3-2025- then the value of 0-113-0-223- - -0-993 is close to-A- 0-2695B- 0-3695C- 2-695D- 3-695

The correct option is C 2.695(0.11)^3 + (0.22)^3 +...+ (0.99)^3 = (0.11)^3 (1^3 + 2^3 +... + 9^3) = 0.001331 × 2025 = 2.695275 = 2.695. ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Series

If 13+23+…+ p...

Question

If $1^{3} + 2^{3} + . . . . + p^{3} = 2025$ , then the value of $(0.11)^{3} + (0.22)^{3} + . . . . . + (0.99)^{3}$ is close to:

0.2695

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.3695

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.695

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3.695

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

1^{3} + 2^{3} + . . . . . . + 9^{3}

(0.11)^{3} + (0.22)^{3} + . . . . + (0.99)^{3}

$1^{3} + 2^{3} + . . . . . . . + 9^{3} = 2025, t h e n t h e v a l u e o f {0.11}^{3} + {0.22}^{3} + . . . . . . + {0.99}^{3} i s c l o s e t o$

1^{3} + 2^{3} + 3^{3} + . . . . . + 9^{3} = 2025

(0.11)^{3} + (0.22)^{3} + . . . . . + (0.99)^{3}

1^{3} + 2^{3} + . . . + 9^{3} = 2025

(0.11)^{3} + (0.22)^{3} + . . . (0.99)^{3}

1^{3} + 2^{3} + . . . + 9^{3} = 2025

(0.11)^{3} + (0.22)^{3} + . . . (0.99)^{3}

Join BYJU'S Learning Program