If 13-23- p 3-2025- then the value of 0-113-0-223- - -0-993 is close to-A- 0-2695B- 0-3695C- 2-695D- 3-695

The correct option is C 2.695(0.11)^3 + (0.22)^3 +...+ (0.99)^3 = (0.11)^3 (1^3 + 2^3 +... + 9^3) = 0.001331 × 2025 = 2.695275 = 2.695. ...

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If 13+23+…+ p...

Question

If $1^{3} + 2^{3} + . . . . + p^{3} = 2025$ , then the value of $(0.11)^{3} + (0.22)^{3} + . . . . . + (0.99)^{3}$ is close to:

0.2695

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0.3695

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2.695

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3.695

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Similar questions

1^{3} + 2^{3} + . . . . . . + 9^{3}

(0.11)^{3} + (0.22)^{3} + . . . . + (0.99)^{3}

$1^{3} + 2^{3} + . . . . . . . + 9^{3} = 2025, t h e n t h e v a l u e o f {0.11}^{3} + {0.22}^{3} + . . . . . . + {0.99}^{3} i s c l o s e t o$

1^{3} + 2^{3} + 3^{3} + . . . . . + 9^{3} = 2025

(0.11)^{3} + (0.22)^{3} + . . . . . + (0.99)^{3}

1^{3} + 2^{3} + . . . + 9^{3} = 2025

(0.11)^{3} + (0.22)^{3} + . . . (0.99)^{3}

1^{3} + 2^{3} + . . . + 9^{3} = 2025

(0.11)^{3} + (0.22)^{3} + . . . (0.99)^{3}

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