If $^{1}^{5} P_{r}$ $= 32760$ , then $r$ $=$

4

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5

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6

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7

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Solution

The correct option is A $4$
We know $^{15} P_{1} = 15$ ,
$^{15} P_{2} = 15 \times 14 = 210$ ,
$^{15} P_{3} = 15 \times 14 \times 13 = 2730$
and $^{15} P_{4} = 15 \times 14 \times 13 \times 12 = 32760$
Therefore, $r = 4$

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