Question

If $1.5x=0.04y$,then value of $\frac{y-x}{y+x}$ is equal to

• A. $0.236$
• B. $0.437$
• C. $0.784$
• D. $0.948$

Answer 1

The correct option is D $0.948$

$1.5x=0.04y$
$y=\frac{1.5}{0.04}x=37.5x$
$y=37.5x$
$\frac{y}{x}=37.5$
Now, $\frac{y-x}{y+x}$
Take x as common from numerator as well as denominator
$\frac{y-x}{y+x}=\frac{x(\frac{y}{x}-1)}{x(\frac{y}{x}+1)}=\frac{(\frac{y}{x}-1)}{(\frac{y}{x}+1)}$
$\frac{y}{x}=37.5$
$\frac{(\frac{y}{x}-1)}{(\frac{y}{x}+1)}=\frac{37.5-1}{37.5+1}=0.948$