Question

If 1.8 grams of glucose is given then find the number of atoms of carbon present in it.

Answer 1

Glucose if $C_6{H}_{12}{O}_6$. Its molecular weight will be
$(12\times 6)+(12\times 1)+(16\times 6)=72+12+96=180gm$
No. of moles in 1.8 gm = $\frac{1.8}{180}=0.01moles$
Now, no of molecules in 1 mole of glucose is =$6.022\times {10}^{23}$
Or, no. of molecules in 0.01 moles of glucose will be =$6.022\times {10}^{21}$
Now, 1 molecule of glucose has 6 carbon atoms
Therefore, no of carbon atoms in $6.022\times {10}^{21}$ molecules of glucose will be = $6.022\times {10}^{21}\times 6$
$=3.6132\times {10}^{22}$ carbon atoms