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Question

If 1,α1,α2,α3,α4,α5,α6, are seven, 7th root of unity them |(3α1)(3α3)(3α5)| is?

A
2186
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B
1093
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C
1023
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D
511
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Solution

The correct option is B 1093
x71=0
(x1)(xα1).....(xα6)=x71
Putting x=3, we get
2.(xα1).(xα2)...(xα6)=2186
|(xα1)|2|(xα3)|2|(xα)|2=1093
|(xα1)(xα3)(xα5)|=1093


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