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Question

If -1 and 3 are the roots of x2+px+q=0, find the values of p and q.

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Solution

Since -1 is a root,

(1)2+p(1)+q=0p+q=1...(1)

Since 3 is a root,

32+3p+q=03p+q=9...(2)

Subtracting equation (2) from equation (1), 4p=8p=2

Substituting this in equation (1), 2+q=1q=3


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