Let p(x) = x 3 – ax 2 – 13x + b
Now, p(1) = 0
(1)3 – a(1)2 –13(1) + b = 0
⇒ –a + b = 12 .....(1)
Now, , p(– 3) = 0
⇒ (– 3)3 – a (– 3)2 – 13(– 3) + b = 0
⇒ 9a – b = 12 .....(2)
Adding, equation (1) and (2),
8a = 24
⇒ a = 3
b = 12 + 3 = 15 (Using equation (1))
∴ a = 12 and b = 15