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Question
If 1cal=4.2J, then 0.2calg−1oC−1=.........Jkg−1K−1
If 1cal=4.2J, then 0.2calg−1oC−1=.........Jkg−1K−1
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Solution
The correct option is C 840
1cal=4.2J,1kg=1000g then 1calg−1oC−1=4.2Jg−1oC−11calg−1oC−1=4.2∗103Jkg−1oC−1
1calg−1oC−1=4200Jg−1oC−1
And multiplying both the side by 0.2we have0.2calg−1oC−1=0.2∗4200Jg−1oC−1
0.2calg−1oC−1=840Jg−1oC−1
1cal=4.2J,1kg=1000g
then 1calg−1oC−1=4.2Jg−1oC−1
1calg−1oC−1=4.2∗103Jkg−1oC−1
1calg−1oC−1=4200Jg−1oC−1
And multiplying both the side by 0.2
we have
0.2calg−1oC−1=0.2∗4200Jg−1oC−1
0.2calg−1oC−1=840Jg−1oC−1
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