MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Molecular Speeds - Vrms, Vavg, Vmps

If 1 g of ...

Question

If $1$ g of $H C l$ and $1$ g of $M n O_{2}$ are heated together, the maximum weight of $C l_{2}$ gas evolved will be :
$M n O_{2} + 4 H C l \to M n C l_{2} + C l_{2} + 2 H_{2} O$

A

2

g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

0.975

g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

0.486

g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

0.972

g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $0.486$ g

Suggest Corrections

thumbs-up

0

Similar questions

M n O_{2} + 4 H C l \to M n C l_{2} + C l_{2} + 2 H_{2} O

1

H C l

1

M n O_{2}

is heated together, the maximum weight of

C l_{2}

gas evolved will be:

0.80

M n O_{2}

146

H C l

M n O_{2} + 4 H C l ⟶ M n C l_{2} + C l_{2} + 2 H_{2} O

0.80

M n O_{2}

146

H C l

react in the following manner:

M n O_{2} + 4 H C l ⟶ M n C l_{2} + C l_{2} + 2 H_{2} O

0.80

M n O_{2}

146

H C l

react, then number of moles of

C l_{2}

formed is (as nearest integer):

M n O_{2} + 4 H C l ⟶ M n C l_{2} + C l_{2} + 2 H_{2} O

M n O_{2} + 4 H C l ⟶ M n C l_{2} + C l_{2} + 2 H_{2} O

0.86

M n O_{2}

48.2

H C l

react, how many grams of

C l_{2}

will be produced? Report your answer to the nearest rounded integer.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Molecular Speeds - Vrms, Vavg, Vmps

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon