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Atomic Mass

If 1 gm of ...

Question

If 1 gm of $H C l$ and 1 gm of $M n O_{2}$ are heated together, the maximum weight of $C l_{2}$ gas evolved will be:

A

2 gm

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B

0.975 gm

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C

0.486 gm

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D

0.972 gm

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Solution

The correct option is D 0.486 gm
$M n O_{2} + 4 H C l \to C l_{2} + M n C l_{2} + 2 H_{2} O$
As $H C l$ is present in limited amount, it will be limiting reagent and the amount of chlorine gas produced will be calculated according to the amount of $H C l$ present.
Moles of $H C l = \frac{1}{36.5}$
Moles of $C l_{2} = \frac{1}{4} \times \frac{1}{36.5}$
Weight of $C l_{2} g a s = \frac{1}{4} \times \frac{1}{36.5} \times 71 = 0.486 g m$

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