If (1 + i) z = (1 - i) ¯¯¯z, then show that z = -i¯¯¯z.
(1 + i) z = (1 - i) ¯¯¯z
⇒ z=(1−i)(1+i)¯¯¯z⇒ z=(1−i)(1−i)(1+i)(1−i)¯¯¯z [Rationalizing the denominator]⇒ z=(1−2i−1)(1+1)¯¯¯z⇒ z=−2i2¯¯¯z⇒ z=−i¯¯¯z