Question

If 1 is a zero of the polynomial $a{x}^2-3(a-1)x-1$ then find the value of a.

Answer 1

One of the zeroes of the polynomial is 1.

i.e. when x = 1 p(x) = 0

Let's put the value of x in the given polynomial

we get , $a(1{)}^2-3(a-1)1-1=0$

$a-3a+3-1=0$

$-2a+2=0$

$a=\frac{-2}{-2}$

$a=1$