If $- 1$ is one of the roots of the equation $(m - 2) x^{2} + 8 x + (m + 4) = 0,$ then $m =$

- 3

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3

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- 5

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Solution

The correct option is B $3$
Given: $(m - 2) x^{2} + 8 x + (m + 4) = 0$
Comparing with $a x^{2} + b x + c = 0,$ we get:
$a = m - 2; b = 8; c = m + 4$
Now, $- 1$ is one of the roots of the equation:
$\Rightarrow a - b + c = 0 \Rightarrow m - 2 - 8 + m + 4 = 0 \Rightarrow 2 m = 6 \Rightarrow m = 3$

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