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Question

If 1 is one of the roots of the equation (m2)x2+8x+(m+4)=0, then m=

A
3
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B
5
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3
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Solution

The correct option is A 3
Given: (m2)x2+8x+(m+4)=0 and 1 is one of the roots of the equation.
Now, we know if 1 is of the roots of the equation ax2+bx+c=0
ab+c=0m28+m+4=02m=6m=3

2nd Method:
If 1 is one of the roots of the equation, then the value of equation at x=1 is 0.
(m2)(1)2+8(1)+(m+4)=0
m28+m+4=02m=6m=3

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