If 1 is the root of equation ay^2+at+3=0 and y^2+y+b=0. Find 'a' and 'b'.

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Solution

If 1 is the root of the given equations then it would satisfy the conditions ;

a(1)^2+at+3 = 0
a+at = -3
a(1+t) = -3
a = -3/(1+t)

(1)^2+(1)+b =0
2 + b = 0
b = -2

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