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Question
If 1 is the zero of the polynomial p(x) = ax² - 3(a - 1) x - 1,then find the value of a.
If 1 is the zero of the polynomial p(x) = ax² - 3(a - 1) x - 1,then find the value of a.
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Solution
One of the zeroes of the polynomial is 1 .
i.e. when x = 1 p(x) = 0
Let's put the value of x in the given polynomial
we get , a(1)2 -3(a - 1)1 - 1 = 0
a - 3a +3 -1 = 0
-2a +2 =0
a = -2 / -2
a = 1
One of the zeroes of the polynomial is 1 .
i.e. when x = 1 p(x) = 0
Let's put the value of x in the given polynomial
we get , a(1)2 -3(a - 1)1 - 1 = 0
a - 3a +3 -1 = 0
-2a +2 =0
a = -2 / -2
a = 1
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