Question

If $1$ is zero of the polynomial $f\left(x\right)=a^2{x}^2-3ax+3x-1$, then $a$ is equal to

• A. $-1$
• B. $2$
• C. $-2$
• D. $0$

Answer 1

Answer: (B)

$2$

If $1$ is the zero of the polynomial $f\left(x\right)=a^2{x}^2-3ax+3x-1$
Then, $f\left(x\right)=0$
$=>a^2(1{)}^2-3a(1)+3(1)-1=0$
$=>a^2-3a+3-1=0$
$=>a^2-3a+2=0$
$=>a^2-2a-a+2=0$
$=>a(a-2)-1(a-2)=0$
$=>(a-2)(a-1)=0$
$a=2$
Hence, option $B$ is correct.