If $1 J$ of work is done in bringing $1 C o u l o m b$ of positive charge from infinity to a point in the electric field, then the potential of that point is:

1 C o u l o m b

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1 V o l t

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1 P a s c a l

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1 F a r a d

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Solution

The correct option is A $1 V o l t$
$w o r k d o n e = Q Δ V$
$Δ V = \frac{w o r k d o n e}{Q} = \frac{1 J}{1 C} = 1 V$

Option B is correct.

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The electric potential at a point is the amount of work done in bringing a unit positive charge from infinity to that point.

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