If $1 k g$ of water is mixed with $2 k g$ of liquid of density $3 g / c m^{3}$ , then the average density of mixture will be ?

2.4 g / c m^{3}

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1.5 g / c m^{3}

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2.1 g / c m^{3}

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1.8 g / c m^{3}

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Solution

The correct option is D $1.8 g / c m^{3}$
$Mass water = 1 k g$

$Mass liquid = 2 k g$

$density liquid = 3 g / {c m}^{3}$

$density water = lg / {c m}^{3}$

$density = \frac{totol mass}{total vol.}$

$= \frac{1000 + 2000}{\frac{1000}{1} + \frac{2000}{3}}$

$= \frac{3000 \times 3}{5000}$

$= \frac{9}{5} = 1.8 {g c m}^{- 3}$

Ans: $(D)$

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