If 1- a- 2- then - a-2- a-1 - a-2- a-1 -

The correct option is C 2 √(a 2 √(a 1)) √(a + 2 √(a 1)) ⇒√((√(a 1))^2 2 (1) √(a 1) + 1^2) √((√((a 1)))^2 + 2 √(a 1) + 1^2) ...

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Irrational Numbers on the Number Line

If 1≤ a≤ 2,...

Question

If $1 \leq a \leq 2$ , then $\sqrt{a - 2 \sqrt{a - 1}} - \sqrt{a + 2 \sqrt{a - 1}} =$ .......

2

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2 \sqrt{a - 1}

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- 2

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1

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Solution

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Similar questions

1 \leq a \leq 2

\sqrt{a + 2 \sqrt{a - 1}} + \sqrt{a - 2 \sqrt{a - 1}} = 2

1 \leq a \leq 2

(a - 1) > 1

A = ⎡ ⎢ ⎣ \begin{matrix} 2 & 2 & 1 1 & 3 & 1 1 & 2 & 2 \end{matrix} ⎤ ⎥ ⎦,

A^{- 1} + (A - 5 I) (A - I)^{2} =

a^{2} + \frac{1}{a^{2}}

A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 3 - 1 & 1 & 2 2 & 2 & 4 \end{matrix} ⎤ ⎥ ⎦

(A^{2} - 5 A) A^{- 1} =

x = a^{1 / 2} + a^{- 1 / 2}, y = a^{1 / 2} - a^{- 1 / 2}

(x^{4} - x^{2} y^{2} - 1) + (y^{4} - x^{2} y^{2} + 1)

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