If - 1 - x - y - 1 such that sin - 1 x - sin - 1 y - - 2 - find the value of cos - 1 x - cos - 1 y-

sin^ 1x+sin^ 1y=π2 ⇒sin^ 1x=π2 sin^ 1y=cos^ 1y also, sin^ 1y=π2 sin^ 1x=cos^ 1x ∴cos^ 1x+cos^ 1y=sin^ 1x+sin^ 1y=π2 ...

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Trigonometric Equations

If - 1 ≤ x ...

Question

If $- 1 \leq x, y \leq 1$ such that ${sin}^{- 1} x + {sin}^{- 1} y = \frac{π}{2},$ find the value of ${cos}^{- 1} x + {cos}^{- 1} y .$

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Similar questions

{sin}^{- 1} x + {sin}^{- 1} y = \frac{π}{2}

{sin}^{- 1} x = {cos}^{- 1} y

\sin^{- 1} x + \sin^{- 1} y = \frac{π}{3}

\cos^{- 1} x - \cos^{- 1} y = \frac{π}{6}

{sin}^{- 1} x + {sin}^{- 1} y = \frac{2 π}{3}

{cos}^{- 1} x + {cos}^{- 1} y

(x, y)

{sin}^{- 1} x + {sin}^{- 1} y = \frac{2 π}{3}

{cos}^{- 1} x - {cos}^{- 1} y = \frac{π}{3}

\begin{matrix} {sin}^{- 1} x + {sin}^{- 1} y = \frac{2 π}{3}, \end{matrix}

\begin{matrix} {cos}^{- 1} x + {cos}^{- 1} y = \end{matrix}

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