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Question

If 1 mol of A and 1.5 mol of B and and 0.5 mol of C are placed in 1 litre vessel and allowed to attain the equilibrium. The final concentration of C is 0.7 mol L1, the value of Kc is;

A
0.70
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B
0.46
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C
0.50
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D
0.25
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Solution

The correct option is B 0.70
A+BC
A B C
Initial 1 1.5 0.5
change 1-x 1.5-x 0.5+x
equilibrium 0.8 1.3 0.7
x = 0.7-0.5 = 0.2
Kc=[0.7]0.5[0.8][1.3]1.5=0.70





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