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Byju's Answer
Standard X
Physics
Thermal Energy
If 1 mole of ...
Question
If 1 mole of aqueous nitric acid is formed, calculate total heat released :
4
N
H
3
(
g
)
+
5
O
2
(
g
)
→
4
N
O
(
g
)
+
6
H
2
O
g
2
N
O
g
+
O
2
(
g
)
→
2
N
O
2
(
g
)
3
N
O
2
(
g
)
+
H
2
O
(
g
)
→
2
H
N
O
3
(
a
q
)
+
N
O
(
g
)
A
-986 KJ
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B
-246.5 KJ
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C
-493 KJ
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D
None of these
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Solution
The correct option is
C
-493 KJ
First multiply the first equation by 3, second by 6 and third by 4.
12
N
H
3
(
g
)
+
15
O
2
(
g
)
→
12
N
O
(
g
)
+
18
H
2
O
g
Δ
H = -2721 kJ
12
N
O
g
+
6
O
2
(
g
)
→
12
N
O
2
(
g
)
Δ
H = -678 kJ
12
N
O
2
(
g
)
+
4
H
2
O
(
g
)
→
8
H
N
O
3
(
a
q
)
+
4
N
O
(
g
)
Δ
H = -556 kJ
Adding up all the three equations,
12
N
H
3
(
g
)
+
15
O
2
(
g
)
→
12
N
O
(
g
)
+
6
O
2
(
g
)
+
12
N
O
2
(
g
)
+
4
H
2
O
(
g
)
12
N
O
(
g
)
+
18
H
2
O
g
+
12
N
O
2
(
g
)
8
H
N
O
3
(
a
q
)
+
4
N
O
(
g
)
Δ
H = -2721 kJ - 678 kJ - 556 kJ
=
Δ
H = -3955 kJ
1 mole
H
N
O
3
×
−
3955
K
J
/ 8 mol
H
N
O
3
= -493 KJ
Therefore, the correct option is C.
Suggest Corrections
0
Similar questions
Q.
The following sequence of reaction occurs in commercial production of aqueous nitric acid.
4
N
H
3
(
g
)
+
5
O
2
(
g
)
→
4
N
O
(
g
)
+
6
H
2
O
(
l
)
Δ
H
=
−
904
k
J
.
.
.
(
1
)
2
N
O
(
g
)
+
O
2
(
g
)
→
2
N
O
2
(
g
)
Δ
H
=
−
112
k
J
.
.
.
(
2
)
3
N
O
2
(
g
)
+
H
2
O
(
l
)
→
2
H
N
O
3
(
a
q
)
+
N
O
(
g
)
Δ
H
=
−
140
k
J
.
.
.
(
3
)
Determine the magnitude of total heat
(
i
n
kJ/mole
)
liberated at constant pressure for the production of exactly 1 mole of aqueous nitric acid by this process
Q.
The following sequence of reaction occurs in commercial production of aqueous nitric acid.
4
N
H
3
(
g
)
+
5
O
2
(
g
)
→
4
N
O
(
g
)
+
6
H
2
O
(
l
)
Δ
H
=
−
904
k
J
.
.
.
(
1
)
2
N
O
(
g
)
+
O
2
(
g
)
→
2
N
O
2
(
g
)
Δ
H
=
−
112
k
J
.
.
.
(
2
)
3
N
O
2
(
g
)
+
H
2
O
(
l
)
→
2
H
N
O
3
(
a
q
)
+
N
O
(
g
)
Δ
H
=
−
140
k
J
.
.
.
(
3
)
Determine the magnitude of total heat
(
i
n
kJ/mole
)
liberated at constant pressure for the production of exactly 1 mole of aqueous nitric acid by this process
Q.
What would happen to the equilibrium system shown here if oxygen were added?
4
N
H
3
(
g
)
+
5
O
2
(
g
)
⇔
4
N
O
(
g
)
+
6
H
2
O
(
g
)
Q.
Nitric acid can be produced from ammonia in a three steps process:
4
N
H
3
(
g
)
+
5
O
2
(
g
)
→
4
N
O
(
g
)
+
6
H
2
O
(
g
)
(i)
2
N
O
(
g
)
+
O
2
(
g
)
→
2
N
O
2
(
g
)
(ii)
3
N
O
2
(
g
)
+
H
2
O
→
2
H
N
O
3
(
a
q
)
+
N
O
(
g
)
(iii)
Given the percentage yields of (i), (ii) and (iii) reactions as 50 %, 60 % and 80 %. What will be the volume of
N
H
3
(g) at STP required to produce 1575 g of
H
N
O
3
.
Q.
Nitric acid can be produced from ammonia in a three steps process:
4
N
H
3
(
g
)
+
5
O
2
(
g
)
→
4
N
O
(
g
)
+
6
H
2
O
(
g
)
(i)
2
N
O
(
g
)
+
O
2
(
g
)
→
2
N
O
2
(
g
)
(ii)
3
N
O
2
(
g
)
+
H
2
O
→
2
H
N
O
3
(
a
q
)
+
N
O
(
g
)
(iii)
Given the percentage yields of (i), (ii) and (iii) reactions as 50 %, 60 % and 80 %. What will be the volume of
N
H
3
(g) at STP required to produce 1575 g of
H
N
O
3
.
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