The correct option is C n
Since 1,ω,ω2,ω3,.....ωn−1 are the n, nth roots of unity, therefore, we have the identity
=(x−1)(x−ω)(x−ω2).....(x−ωn−1)=xn−1
or (x−ω)(x−ω2)....(x−ωn−1)=xn−1x−1
=xn−1+xn−2+.....+x+1
Putting x = 1 on both sides, we get
(1−ω)(1−ω2)....(1−ωn−1)=n