If 1- - -2- -3- - - n -1 are the n - n th roots of unity- then 1-1-2 -1- n -1 equalsA- 1B- n2C- nD- 0

Since 1, ω, ω ^2, ω ^3, ⋯, ω ^n 1 are the n, nbsp; n^th nbsp;roots of unity, ∴ nbsp; nbsp;(x 1)(x ω )(x ω ^2) ⋯ (x ω^n 1) = x^n 1 ⇒ nbsp; (x ...

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nth Root of a Complex Number

If 1, ω, ω2, ...

Question

If $1, ω, ω^{2}, ω^{3} . . . . ., ω^{n - 1}$ are the n, $n^{t h}$ roots of unity, then $(1 - ω) (1 - ω^{2}) . . . . . (1 - ω^{n - 1})$ equals

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n^{2}

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Similar questions

1, ω, ω^{2}, ω^{3} . . . . ., ω^{n - 1}

n^{t h}

(1 - ω) (1 - ω^{2}) . . . . . (1 - ω^{n - 1})

ω, ω^{2}, ω^{3}, . . . . . . . . ω^{n - 1}

(1 - ω) (1 - ω^{2}) . . . . . . . (1 - ω^{n - 1})

1, ω, ω^{2}, . . . . ω^{n - 1}

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(9 - ω) \cdot (9 - ω^{2}) \cdot (9 - ω^{3}) . . . (9 - ω^{n - 1})

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(5 - ω) (5 - ω^{2}) . . . (5 - ω^{n - 1}) =

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n^{th}

x^{n} = 1.

(5 - ω) (5 - ω^{2}) \dots (5 - ω^{n - 1})

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