If 1-2-n-1 are nth roots of unity- then the value of 5-5-2-5-n-1-

The correct option is A 5^n 1/4 x ^ n 1=0 has n roots (of unity).Thus, x ^ n 1=(x 1)(x ω )(x ω nbsp;^ 2 )...(x ω nbsp;^ n 1 ) .Substitute ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Integration to Solve Modified Sum of Binomial Coefficients

If 1,ω,ω2,....

Question

If $1, ω, ω^{2}, . . ., ω^{n - 1}$ are $n^{t h}$ roots of unity, then the value of $(5 - ω) (5 - ω^{2}) . . . (5 - ω^{n - 1}) =$

\frac{5^{n} - 2}{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{5^{n} + 2}{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{5^{n} + 1}{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{5^{n} - 1}{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

Suggest Corrections

Similar questions

1, ω, ω^{2}, \dots, ω^{n - 1}

n^{th}

x^{n} = 1.

(5 - ω) (5 - ω^{2}) \dots (5 - ω^{n - 1})

ω, ω^{2}, ω^{3}, . . . . . . . . ω^{n - 1}

(1 - ω) (1 - ω^{2}) . . . . . . . (1 - ω^{n - 1})

1, ω, ω^{2}, . . . . ω^{n - 1}

n, n^{t h}

(9 - ω) \cdot (9 - ω^{2}) \cdot (9 - ω^{3}) . . . (9 - ω^{n - 1})

1, ω, ω^{2}, ω^{3} . . . . ., ω^{n - 1}

n^{t h}

(1 - ω) (1 - ω^{2}) . . . . . (1 - ω^{n - 1})

I f 1, ω, ω^{2}, ω^{3} . . . . ., ω^{n - 1} a r e t h e n, n^{t h} r o o t s o f u n i t y, t h e n (1 - ω) (1 - ω^{2}) . . . . . (1 - ω^{n - 1}) e q u a l s

Join BYJU'S Learning Program