If $1$ out of every $50$ people who play a certain game win a prize, what percent of people lose?

1

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2

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99

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98

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Solution

The correct option is D $98$ %
$1$ out of every $50$ people win.
i.e. Number of people lose $= 50 - 1 = 49$
Percentage of people who lose $= \frac{49}{50} \times 100 = 98$ %.

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If 1 out of every 50 people who play a certain game win a prize, what percent of people lose?

The correct option is D 98%1 out of every 50 people win.i.e. Number of people lose =50−1=49Percentage of people who lose =4950×100=98%.

If $1$ out of every $50$ people who play a certain game win a prize, what percent of people lose?

The correct option is D $98$ %
$1$ out of every $50$ people win.
i.e. Number of people lose $= 50 - 1 = 49$
Percentage of people who lose $= \frac{49}{50} \times 100 = 98$ %.