Question

If 1 part of a blue pigment requires 45 ml of base, how much blue pigment should we mix with 900 ml of base.If the ml of the base is doubled calculate how much of blue pigment it will now require? [4 MARKS]

Answer 1

Concept: 1 Mark
Solution: 3 Marks

$\begin{array}{ccc}Partofbluepigment& 1& x\\ Partofbase& 45& 900\end{array}$

$\frac{1}{45}=\frac{x}{900}$

$\frac{900}{45}=x$

$x=20$

20 parts of blue pigment is required to mix with the base.