If $1$ part of a red pigment requires $75$ mL of base, how much red pigment should we mix with $800$ mL of base.

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Solution

Let x pigment required with mix to base.
$\frac{1}{75} = \frac{x}{1800}$
$\Rightarrow x = \frac{1800}{75} = 24$

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In Question 2 above, if 1 part of a red pigment requires 75 mL of base, how much red pigment should we mix with 1800 mL of base?

Question 03.
In Question 2 above, if 1 part of a red pigment requires 75 mL of base, how much red pigment should we mix with 1800 mL of base?

Question 03.
In Question 2 above, if 1 part of a red pigment requires 75 mL of base, how much red pigment should we mix with 1800 mL of base?

Q. 2A mixture of paint is prepared by mixing

1

part of red pigments with

8

parts of base. In the following table, find the parts of base that need to be added

Parts of red pigment	$1$	$4$	$7$	$12$	$20$
Parts of base	$8$	$\dots$	$\dots$	$\dots$	$\dots$

1

part of a red pigment requires

75

mL of base, how much red pigment should we mix with

1800

mL of base?

A mixture of paint is prepared by mixing 1 part of red pigment with 8 parts of base. In the following table, find the parts of base that need to be added.
If 1 part of a red pigment requires 75 mL of base, how much red pigment should we mix with 1800 mL of base?

$\begin{matrix} P a r t s o f r e d p i g m e n t & 1 & 4 & 7 & 12 & 20 P a r t s o f b a s e & 8 \end{matrix}$ [3 MARKS]

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If 1 part of a red pigment requires 75 mL of base, how much red pigment should we mix with 800 mL of base.

Let x pigment required with mix to base.175=x1800⇒x=180075=24

If $1$ part of a red pigment requires $75$ mL of base, how much red pigment should we mix with $800$ mL of base.

Let x pigment required with mix to base.
$\frac{1}{75} = \frac{x}{1800}$
$\Rightarrow x = \frac{1800}{75} = 24$