If 1-sin 2 A-3 sin A cos A- then prove that tan A-1 or 1 - 2

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Range of Trigonometric Ratios from 0 to 90 Degrees

If 1+sin 2 A=...

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If 1+ sin²A = 3sinAcosA , then prove that tanA=1 or 1/2

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\frac{cos 2 A}{1 - sin 2 A} = \frac{1 + tan A}{1 - tan A}

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\frac{tan (A + B)}{tan (A - B)} = \frac{λ + 1}{λ - 1}

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