If 1 volume of H2 reacts with 1 volume of O2 to form 1 volume of H20. Then when 4 L of H2 & 3.2 L of O2 will be mixed. What will be the composition by volume of the remaining unreacted gaseous mixture?
0.8 L
Since 1 volume of oxygen reacts with 1 volume of hydrogen.
So, 3.2 L of O2 reacts with 3.2 L of H2.
Therefore (4- 3.2)= 0.8 L of hydrogen will remain un-reacted.