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Question

If 1 volume of H2 reacts with 1 volume of O2 to form 1 volume of H20. Then when 4 L of H2 & 3.2 L of O2 will be mixed. What will be the composition by volume of the remaining unreacted gaseous mixture?


A

2L

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B

0.6 L

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C

4 L

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D

0.8 L

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Solution

The correct option is D

0.8 L


Since 1 volume of oxygen reacts with 1 volume of hydrogen.

So, 3.2 L of O2 reacts with 3.2 L of H2.

Therefore (4- 3.2)= 0.8 L of hydrogen will remain un-reacted.


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