wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If (1+x)n=C0+C1x+..+Cnxn, then the value of nr=0ns=0(Cr+Cs) is equal to

A
(n+1)2n+1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(n1)2n+1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(n+1)2n
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(n1)2n
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A (n+1)2n+1
We have, nr=0ns=0(Cr+Cs)

=nr=0ns=0Cr+nr=0ns=0Cs

=ns=0(nr=0Cr)+nr=0(ns=0Cs)

=ns=02n+nr=02n

=(n+1)2n+(n+1)2n
=(n+1)2n+1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sum of Coefficients of All Terms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon