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Question

If (1+x)n=C0+C1x+..+Cnxn, then the value of nr=0ns=0(Cr+Cs) is equal to

A
(n+1)2n+1
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B
(n1)2n+1
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C
(n+1)2n
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D
(n1)2n
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Solution

The correct option is A (n+1)2n+1
We have, nr=0ns=0(Cr+Cs)

=nr=0ns=0Cr+nr=0ns=0Cs

=ns=0(nr=0Cr)+nr=0(ns=0Cs)

=ns=02n+nr=02n

=(n+1)2n+(n+1)2n
=(n+1)2n+1

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