CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If (1 + x)n = nC0 + nC1x+ nC2x2 + ... + nCnxnthen the value of nC0 + 3 nC1 + 9 nC2+ ... + 3n nCnis
______

A
2n
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3n
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2n1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4n
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 4n
If we substitute x=3 in the above expression, we get
(1 + 3)n = nC0 30 + nC1 31 + nC2 32 + ... + nCn3n = 4n
Hence, Option d.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
General Term
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon