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Question

If (1 + x)n = nC0 + nC1x+ nC2x2 + ... + nCnxnthen the value of nC0 + 3 nC1 + 9 nC2+ ... + 3n nCnis
______

A
2n
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B
3n
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C
2n1
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D
4n
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Solution

The correct option is D 4n
If we substitute x=3 in the above expression, we get
(1 + 3)n = nC0 30 + nC1 31 + nC2 32 + ... + nCn3n = 4n
Hence, Option d.

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