CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If (1+x)n=nr=0nCrxr and nr=01nCr=a, then the value of 0in 0jn(inCi+jnCj) is equal to

A
n2a
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
n22a
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
na2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
na(n+1)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D na(n+1)
Given, a=nr=01nCr=nr=01nCnr
Let,
y=0in 0jn(inCi+jnCj)
=0in 0jn(ninCni+njnCnj) [nr=0rnCr=nr=0nrnCnr]
=n0in 0jn(1nCni+1nCnj)y=n0in(n+1nCni+a)y
2y=n{a(n+1)+a(n+1)}
y=na(n+1)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sum of Product of Binomial Coefficients
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon