wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If (1−x+x2)n=a0+a1x+a2x2+...........+a2nx2n and a0,a1,a2,...........,a2n are in arithmetic progression, then an is

A
1n+1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1n1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
12n+1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
12n1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 12n+1
Substituting x=1 in the above mentioned binomial expression we get
1=a0+a1+a2+...an+..a2n
Since they all are in A.P
1=(a0+a2n)+(a1+a2n1)+...an
=1=2an+2an+2an...an
1=2nan+an
an(2n+1)=1
an=12n+1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Geometric Progression
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon