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Question

If (1y)(1+2x+4x2+8x3+16x4+32x5)=1y6, where y1,x12, then the value of yx is

A
12
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B
2
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C
2524
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D
2425
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Solution

The correct option is B 2
(1y)(1+2x+4x2+8x3+16x4+32x5)=1y6(1y)(1((2x)61)2x1)=1y6(2x)612x1=y61y1y=2xyx=2

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