If $10^{20}$ electrons flow from the black body to the red body through the copper wire in 8 seconds, then find the current flowing between them.

2 A

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0.2 A

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8 A

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1 A

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Solution

The correct option is A
2 A

We know that, q = ne

Also, I = $\frac{q}{t}$

Hence, I = $\frac{n e}{t}$ = $\frac{10^{20} \times 1.6 \times 10^{- 19}}{8}$ = 2 A

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If 1020 electrons flow from the black body to the red body through the copper wire in 8 seconds, then find the current flowing between them.

The correct option is A 2 A We know that, q = ne Also, I = qt Hence, I = net = 1020×1.6×10−198 = 2 A

If $10^{20}$ electrons flow from the black body to the red body through the copper wire in 8 seconds, then find the current flowing between them.

The correct option is A
2 A

We know that, q = ne

Also, I = $\frac{q}{t}$

Hence, I = $\frac{n e}{t}$ = $\frac{10^{20} \times 1.6 \times 10^{- 19}}{8}$ = 2 A