If $10^{2 x} = 25$ then find $10^{- x}$ .

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Solution

Given,
$10^{2 x} = 25$
or, $(10^{x})^{2} = 25$
or, $10^{x} = \sqrt{25}$
or, $10^{x} = 5$
or, $10^{- x} = 5^{- 1}$
or, $10^{- x} = \frac{1}{5}$

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