If $10^{6}$ electrons/sec. are flowing through an area of cross section of $10^{- 4} m^{2}$ then the current will be :-

1.6 \times 10^{- 7}

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1.6 \times 10^{- 13}

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1 \times 10^{- 6}

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1 \times 10^{2}

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Solution

The correct option is B $1.6 \times 10^{- 13}$ A
Current is the total charge flow per sec. Thus current $i = n e = 10^{6} (1.6 \times 10^{- 19} = 1.6 \times 10^{- 13} A$

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If 106 electrons/sec. are flowing through an area of cross section of 10−4m2 then the current will be :-

The correct option is B 1.6×10−13 ACurrent is the total charge flow per sec. Thus current i=ne=106(1.6×10−19=1.6×10−13A

If $10^{6}$ electrons/sec. are flowing through an area of cross section of $10^{- 4} m^{2}$ then the current will be :-

The correct option is B $1.6 \times 10^{- 13}$ A
Current is the total charge flow per sec. Thus current $i = n e = 10^{6} (1.6 \times 10^{- 19} = 1.6 \times 10^{- 13} A$