If 10 g of a sample of water contains 16.2 g of $C a (H C O_{3})_{2}$ , then the hardness of water is:

200 ppm

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300 ppm

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60 ppm

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100 ppm

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Solution

The correct option is B 100 ppm
If density of water $= 1 g / m l$
$∴ 10 m l$ water contains $16.2 m g$ $C a (H C O_{3})_{2}$ .
$∴ 1 L$ water contains $16.2 \times 10^{2} m g$ $C a (H C O_{3})_{2}$ .
Equivalent of $C a C O_{3} = 16.2 \times 10^{2} \times \frac{100}{162} = 100$
$∴$ Hardness in $p p m = 100 p p m$

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