If 10 is a root of quadratic equation $11 x^{2} - k x - 120 = 0$ , then the value of $k$ is _________.

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Solution

Finding the value of $k$ :
Since, 10 is a root of the given quadratic equation therefore it will satisfy the quadratic equation.
Substitute $x = 10$ in the given equation:
$∴ 11 {(10)}^{2} - 10 k - 120 = 0 \Rightarrow 11 (100) - 10 k - 120 = 0 \Rightarrow 1100 - 120 = 10 k \Rightarrow k = 98$
Final Answer:
Hence, the value of k is 98.

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