Question

If ${10}^x=64$, what is the value of ${10}^{\frac{x}{2}+1}$?

Answer 1

Given

${10}^x=64$

Then,

${10}^{\frac{x}{2}+1}={10}^{\frac{x}{2}}\times 10$

$=[{10}^x{]}^{\frac{1}{2}}\times 10$

$=[64{]}^{\frac{1}{2}}\times 10$

$=8\times 10$

$=80$