Question

If ${10}^x=64$, what is the value of ${10}^{\frac{x}{2}+1}$

• A. 18
• B. 42
• C. 80
• D. 81

Answer 1

Answer: (C)

80

${10}^x=64$
$\Rightarrow ({10}^x{)}^{\frac{1}{2}}={64}^{\frac{1}{2}}$
$\Rightarrow {10}^{\frac{x}{2}}=\sqrt{64}$
$\Rightarrow {10}^{\frac{x}{2}}=8$

$\Rightarrow {10}^{\frac{x}{2}}\times 10=8\times 10$

$\therefore {10}^{(\frac{x}{2}+1)}=80$