Question

If ${10}^x=64,whatisthevalueof{10}^{\frac{x}{2}+1}?$

• A. 18
• B. 42
• C. 80
• D. 81

Answer 1

The correct option is C

80

${10}^x=64\Rightarrow \sqrt{{10}^x}=\sqrt{64}\Rightarrow ({10}^x{)}^{\frac{1}{2}}=8\Rightarrow {10}^{\frac{x}{2}}=8Now,{10}^{\frac{x}{2}+1}={10}^{\frac{x}{2}}\times {10}^1=8\times 10=80$