If 100 calories of heat are added to a system and a work of 50 calories is done on the system, calculate the energy change of the system

150 calories

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50 calories

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-50 calories

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-150 calories

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Solution

The correct option is A 150 calories
The first law of thermodynamics can be given by $Δ U = q + w$

When $q$ is positive, it is the heat added to the system.

When $q$ is negative, it is the heat taken from the system.

When $w$ is positive, it is the work done on the system.

When $w$ is negative, it is the work done by the system.

Heat added to the system $q$ = $100 c a l o r i e s$

Work done on the system $w = 50 c a l o r i e s$

$Δ U = q + w = 100 + 50 = 150 c a l o r i e s$

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