Question

If 100 J is the energy required per second for the appliance to run. What is the power consumed, if it operates at 220V.

• A. 22 W
• B. 22000 W
• C. 100 W
• D. Data insufficient

Answer 1

The correct option is C

100 W

Power of an appliance = $\frac{ElectricalEnergy\left(inJoule\right)}{Time\left(insecond\right)}$
Power of an appliance = $\frac{100J}{1s}$ = 100 W
Thus, if an electrical appliance consumes 100 J of electrical energy in 1 second, the power of the appliance is 100 W.